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I need the name of each layer in an .msd, but I could not find support using arcpy (ArcGIS 10.0). Is there a method I missed?

In the current workflow, since I am publishing the document, I use the REST service:

descriptionUrl = url + "/ArcGIS/rest/services/" + mapServer + "/MapServer?f=json"  
restResponseFp = urllib.urlopen(descriptionUrl)
mapDescription =json.load(restResponseFp)
layerNames = [str(layer["name"]) for layer in mapDescription["layers"]]
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1 Answer

up vote 3 down vote accepted
import zipfile
from xml.etree.cElementTree import iterparse

zz = zipfile.ZipFile('C:\\Temp\\Untitled.msd')

serviceNames = []
for name in zz.namelist():
    if name == "DocumentInfo.xml" or name == "layers/layers.xml":
        pass
    else:
        for _event, elem in iterparse(zz.open(name)):
            if elem.tag == "Name":
                serviceNames.append(elem.text)
                break
zz.close()

Files associated with layers are named like this: layers/featureclassname.xml

Long service names are truncated to make the file name, so we must parse the file contents to handle all cases.

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Thanks! Actually, I notice that since my service names are very long, the xml file name is truncated. Each file associated with a layer must be parsed for the "Name" element to reliably handle long service names. –  majgis Nov 1 '11 at 5:28
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