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I need to show label of each feature based on attribute field value. I know that I can use ${attribute} notation for this purpose. But this approach works only if I make StyleMap and pass it to vector layer constructor. But in this case I can not modify style of each features separately. How I can make layer with labels and with not null value of style property of each feature? My current config:

var custom_style = {
    fill: true,
    fillColor: "#feb24c",
    fillOpacity: 0.2,
    strokeColor: '#3182bd',
    strokeWidth: 1
};

var l = new OpenLayers.Layer.Vector("Coverage", {
    strategies: [new OpenLayers.Strategy.BBOX()],
    protocol: new OpenLayers.Protocol.HTTP({
        url: "http://***:8088/collect",
        format: new ol.Format.GeoJSON()
    }),
    style: custom_style
});

If I add label: ${attribute} to custom_style object, then text ${attribute} will be shown on map, not value of attribute.

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are you having problems because some features have null value? –  neogeomat Oct 28 '13 at 13:54

2 Answers 2

In the case of the label, probably this may work:

label: '${attribute}'

Here I modified your code with it:

var custom_style = {
    fill: true,
    fillColor: "#feb24c",
    fillOpacity: 0.2,
    strokeColor: '#3182bd',
    strokeWidth: 1,
    label: '${attribute}'
};

var l = new OpenLayers.Layer.Vector("Coverage", {
    strategies: [new OpenLayers.Strategy.BBOX()],
    protocol: new OpenLayers.Protocol.HTTP({
        url: "http://***:8088/collect",
        format: new ol.Format.GeoJSON()
    }),
    style: custom_style
});
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Unfortunately, this approach doesn't work as I mentioned above. –  drnextgis May 29 '13 at 1:54
    
could you post some images showing what you have and what you expect? –  Gery May 29 '13 at 10:44

If you want to process each feature and display something different depending on the value of a feature attribute, you can supply a function via the style context that returns different values. Here's an example. However, this approach does use a style map - I'm not sure if you want to avoid using one for some reason.

The value of the label is generated by the assigned function.

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