Hot answers tagged coordinates
You can use QGIS' quadrant placement specifier determined from the line's azimuth to place a better label. The quadrant specifies 8 positions around a point: [ 0=Above Left | 1=Above | 2=Above Right | 3=Left | 4=Over | 5=Right | 6=Below Left | 7=Below | 8=Below Right ] Here's an example around Null Island, creating a table and two views. ...
A very simple brute force approach: take the first points coordinates and convert them from ISN93 / Lambert 1993 to WGS84 degrees using cs2cs in the OSGEO4W shell cs2cs +init=epsg:3057 +to +init=epsg:4326 -f "%%.8f" <ISN93.txt >WGS84.txt build a local omerc CRS on that point, with the "local coordinates" as false Easting and Northing convert the ...
A point inside a polygon canvas = qgis.utils.iface.mapCanvas() aLayer = canvas.layer(0) # or code to select the layer of interest for f in aLayer.getFeatures(): geom = f.geometry() p = geom.pointOnSurface() print p.asPoint() Get Inner Rings canvas = qgis.utils.iface.mapCanvas() aLayer = canvas.layer(0) # or code to select the layer of ...
you can't really convert convert distances in degrees into meters as the size of a degree varies as you approach the poles. convert your locations into a projected coordinate system, then calculate your distances.
Open up the Attribute Table. Turn on editing for the layer. Using the field calculator, calculate a new field with the following info: Name: X Type: Decimal Number (real) Width: 12 Precision:2 For your expression you want: $x Repeat for Y.
i believe this may be an answer https://www.census.gov/geo/reference/centersofpop/animatedmean2010.html http://www.esri.com/news/arcuser/0311/population-drift.html plus this is a really interesting article on the math behind finding the mean center - http://www.ams.org/samplings/feature-column/fcarc-population-center long story short: somewhere in ...
The coordinates must be in the same crs as the layer the diagrams are attached to. Could this be your issue?
Why Using One Fixed Projection Will Not Work For a projection to be of any use at all for distance-related queries, it and its inverse should be continuous almost everywhere. Consider, then, what happens when you pick one point--any point--and start to draw on the map a collection of routes that emanate from that point and move straight away from it, in ...
okay.. as it's in map units this should be fairly straight-forward, within limitations. You already know the height of the label. If it was in points it would be scale-dependant. This assumes a fixed label size, so how well this works depends on how uniform your labels are, and whether or not you use a proportional or fixed-width font (fixed width is easier ...
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