New answers tagged lat-lon
You have to build the proj.4 string for the CRS from the parameters given: +proj=lcc +lat_1=44.883333 +lat_2=45.133333 +lat_0=44.791111 +lon_0=-93.383333 +x_0=152400.000000 +y_0=30480.000000 +a=6378418.9409999996 +b=6357033.3098455509 +towgs84=0,0,0,0,0,0,0 +units=us-ft +no_defs Note that x_0 and y_0 have to be in meters, while false Easting and Northing ...
1 milla náutica es un minuto de arco. En el Ecuador y a nivel del mar eso equivale a 1852m/60=30,86666667m A 33,6º de latitud Sur cos 33º=0,83292 cos 33,6 * 30,866666667m = 25,709m por segundo de arco de longitud a esa latitud.
Why can't you use the Field Calculator to recalculate the Lat/Long once you've done the data transformation? If you need to preserve the original values (for some reason), then add two new columns and calc those with the NAD83 values.
From what I understand (not tested) 35.35 and 34.33 are the coordinates of the parallels (lat_1 and lat_2). The central meridian (lon_0) is -86. Also you might have a false easting of 600 000 As a remark, I've found (on spatialrefeence.org) the below definition for projection in Tennessee, which is slightly different from yours, but could help you fill ...
I declared one point in each octant of the globe, transformed it to XYZ using the equations I had, and then tested martin f's answer. It didn't returned the same points. Then I delved deeper into Wikipedia's equations, and I finally understood how they worked. Then I adapted them. latitude(r, x, y, z) = arcsin(z/r)(180/π) longitude(r, x, y, z) = if (x ...
The wiki reference you cite is based on a mathematical, not a geographic/cartographic, convention, as you say. It does however try to relate the geographic/cartographic equivalents. Here's my interpretation of the equivalencies: Mathematics Geography/Cartography r, radial distance R + h, radius + altitude φ, polar angle 90 - φ, ...
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