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You have to build the proj.4 string for the CRS from the parameters given: +proj=lcc +lat_1=44.883333 +lat_2=45.133333 +lat_0=44.791111 +lon_0=-93.383333 +x_0=152400.000000 +y_0=30480.000000 +a=6378418.9409999996 +b=6357033.3098455509 +towgs84=0,0,0,0,0,0,0 +units=us-ft +no_defs Note that x_0 and y_0 have to be in meters, while false Easting and Northing ...


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1 milla náutica es un minuto de arco. En el Ecuador y a nivel del mar eso equivale a 1852m/60=30,86666667m A 33,6º de latitud Sur cos 33º=0,83292 cos 33,6 * 30,866666667m = 25,709m por segundo de arco de longitud a esa latitud.


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Why can't you use the Field Calculator to recalculate the Lat/Long once you've done the data transformation? If you need to preserve the original values (for some reason), then add two new columns and calc those with the NAD83 values.


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From what I understand (not tested) 35.35 and 34.33 are the coordinates of the parallels (lat_1 and lat_2). The central meridian (lon_0) is -86. Also you might have a false easting of 600 000 As a remark, I've found (on spatialrefeence.org) the below definition for projection in Tennessee, which is slightly different from yours, but could help you fill ...


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I declared one point in each octant of the globe, transformed it to XYZ using the equations I had, and then tested martin f's answer. It didn't returned the same points. Then I delved deeper into Wikipedia's equations, and I finally understood how they worked. Then I adapted them. latitude(r, x, y, z) = arcsin(z/r)(180/π) longitude(r, x, y, z) = if (x ...


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The wiki reference you cite is based on a mathematical, not a geographic/cartographic, convention, as you say. It does however try to relate the geographic/cartographic equivalents. Here's my interpretation of the equivalencies: Mathematics Geography/Cartography r, radial distance R + h, radius + altitude φ, polar angle 90 - φ, ...



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