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I generated points using lines with 4000m spacing in one direction and 4050m in another direction. Pseudo-code to process: Create TIN using any field. Get triangles and edges from TIN using TIN edge and TIN triangle: Sort edges in descending order, sort field shape_length. Calculate their midpoints, shown in red, labelled by OBJECTID: Iterate through ...


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I was able to achieve the following, using the buffer and Minimum Bounding Geometry (extracting the envelope of the buffers) then some manual intervention with the rotate tool. You can then do a final dissolve to return a single polygon. You give no indication how of many of these you need to resolve, a few like your screen shot or hundreds of thousands? If ...


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At the north pole, any "straight line" path from that point is automatically going due south, until you change direction. Likewise, at the south pole, any direct route away is going due north. All "straight lines" (better known as great circles or geodesics), passing through the poles, are known as meridians (or lines of constant longitude) and are ...


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To add some visual clarification-


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Try this : import com.vividsolutions.jts.geom.Coordinate; import javax.measure.unit.NonSI; import org.jscience.geography.coordinates.LatLong; import org.jscience.geography.coordinates.UTM; import org.jscience.geography.coordinates.crs.ReferenceEllipsoid; This method makes the conversion in JAVA and return a Coordinate. Is easy to obtain X and Y from ...


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It is possible using the QGIS "QSpatiaLite" plugin: Install QSpatiaLite plugin create SpatiaLite database connection Open QSpatialite plugin import both polygon and point shapefile to spatialite database (i used the layers "gis_se" as my point layer and "zippoly_gisse" as polygon layer) run a sql statement like select point.id, point.zipcode, poly.id, ...



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