network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 7 months |
| seen | Dec 17 '12 at 22:52 | |
| stats | profile views | 29 |
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Dec 14 |
asked | area weighted average for overlapping polygons |
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Dec 5 |
comment |
Obtain normalized raster average per polygon? Thanks for pointing that out whuber. I went through my questions and rated and accepted them. Regarding the zonal stats as table, you are right it does give me a count. Unfortunately, that count seems to be wrong? If I double check some regions, I count zero raster cells but the zonal stats table output tells me that there are 16? It shouldn't be a projection issue, since both datasets are in the same projections. Any other ideas? |
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Dec 5 |
accepted | Use model builder to select layers by attributes, dissolve them and then merge them |
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Dec 5 |
accepted | calculate coastline at risk |
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Dec 5 |
accepted | joining a table from zonal statistics as table with a layer, problem with reserved names |
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Dec 5 |
awarded | Scholar |
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Dec 5 |
accepted | Zonal Statistics as table creates output but some are Null |
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Dec 5 |
comment |
Obtain normalized raster average per polygon? An individual cell of the raster represent a percentage from 1-100% of total forest killed. The cell size is 100mx100m. Why does zonal statistics as table not offer a simple count? |
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Dec 5 |
asked | Obtain normalized raster average per polygon? |
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Nov 14 |
awarded | Editor |
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Nov 14 |
revised |
joining a table from zonal statistics as table with a layer, problem with reserved names added 21 characters in body |
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Nov 14 |
asked | joining a table from zonal statistics as table with a layer, problem with reserved names |
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Nov 14 |
awarded | Supporter |
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Nov 14 |
awarded | Commentator |
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Nov 14 |
comment |
Use model builder to select layers by attributes, dissolve them and then merge them I came up with a new idea, I had all the IDs in an excel sheet, I added a colum and gave each group of IDs a random value. I then joined this excel sheet to the shapefile based on the ID. Then I could use dissolve on that random value. HURRAY. Thanks for giving me that idea! |
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Nov 13 |
comment |
Use model builder to select layers by attributes, dissolve them and then merge them Hi Aaron, interesting idea, thanks so much, I love learning new approaches! A problem though is that there are usually more IDs than the ones I used in the example. The code block will get really big if I have to type in every time Oldfield == OR etc.. I was hoping to be able to use something like this: Dim output IF [CSDUID] IN('5917005','5917010','5917015','5917021','5917811') THEN output = 1 IF [CSDUID] IN('5917045','5917013','5917022','5917029','5917800') THEN output = 2 ELSE output = 0 END IF but it gives me an error with the THEN.. what am I doing wrong? Does that not work? |
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Nov 13 |
asked | Use model builder to select layers by attributes, dissolve them and then merge them |
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Nov 7 |
awarded | Teacher |
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Nov 7 |
answered | Zonal Statistics as table creates output but some are Null |
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Nov 7 |
comment |
Zonal Statistics as table creates output but some are Null Whuber you are right, sorry I didn't realize that I am excluding other people by doing this. |
