Timeline for Add folder name as attribute to all shapefiles in that folder
Current License: CC BY-SA 3.0
12 events
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| Apr 30, 2015 at 20:58 | comment | added | mr.adam | yes, it would be misleading to give an answer to your second question here, and it's pretty messy to smash it all into the comments like this. | |
| Apr 30, 2015 at 20:55 | comment | added | dhowal | Okay will do @Aaron . New to this so still need to get the hang of things. Thanks for your help. | |
| Apr 30, 2015 at 20:54 | comment | added | Aaron♦ | @DhowalDalal I would recommend opening a follow-up question if you cannot find a solution in the GIS SE archives. | |
| Apr 30, 2015 at 20:51 | comment | added | dhowal | [email protected] , the merge tools do accept a list . | |
| Apr 30, 2015 at 20:50 | comment | added | dhowal |
Thanks @mr.adam , ill give it a try but not sure where to eneter the second bit of code as im quite a newbie .
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| Apr 30, 2015 at 20:50 | comment | added | mr.adam |
like this: for value in fc_dict.values(): arcpy....merge(value,output_fc,etc.) I assume the Merge tools accepts a list for input.
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| Apr 30, 2015 at 20:48 | comment | added | mr.adam |
Sure. What I would do is put fc_dict = {} right underneath fcs = []. While "walking", if filename in fc_dict.keys(): fc_dict[filename].append(os.path.join(dirpath, filename)) else fc_dict[filename] = [os.path.join(dirpath, filename)]. You'll create a dictionary where the key is the filename and the value is a list of all the corresponding files. At the very end of the script, iterate the dictionary and merge each value. dictionaries are one of the best things about python. docs.python.org/2/tutorial/datastructures.html#dictionaries
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| Apr 30, 2015 at 20:41 | vote | accept | dhowal | ||
| Apr 30, 2015 at 20:40 | comment | added | dhowal | That`s right @mr.adam ,well spotted and thank you to @aaron as well for the quick reply. You have both been much help. Any ideas how I can take this one step further and merge all the shaepfiles that have same filenames ? thanks in advance. | |
| Apr 30, 2015 at 20:26 | comment | added | Aaron♦ | Nice addition @mr.adam. | |
| Apr 30, 2015 at 20:17 | comment | added | mr.adam |
Unsure if OP wants full directory path, or just the name of the folder. If just the name is desired, replace dirname = os.path.dirname(fc) with dirname = os.path.basename(os.path.dirname(fc)).
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| Apr 30, 2015 at 19:42 | history | answered | Aaron♦ | CC BY-SA 3.0 |