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Jan 22, 2020 at 16:17 comment added Black Frog I was in-need of bounding box for Open Street Map and this worked perfect.
Nov 24, 2018 at 20:40 comment added ToolmakerSteve I think the point @whuber is making is that there is no benefit to using a complex calculation of distance along Lat and Long, given that you then combine those with pythagorean theorem. You could instead use a much simpler calculation, such as whuber did, or as Ewan Todd does. Use simple linear formulas to convert longitude to miles and latitude to miles, or vice versa. The only "tricky" part is knowing that longitude formula needs the adjustment * cos(lat) when converting degrees to miles, and / cos(lat) when converting miles to degrees.
Oct 17, 2011 at 7:37 vote accept Bex
Oct 17, 2011 at 7:37 comment added Bex My distance will never be more than 100 miles so I don't think it matters. As the inaccuracies will be small with that smaller distance.
Oct 16, 2011 at 14:49 comment added whuber Concerning the edit, the Pythagorean Theorem is ok for small squares, but in general it does not hold for spherical right triangles. It's strange, then, that your code uses spherical trigonometry together with this approximation based on plane geometry.
Oct 13, 2011 at 7:58 history edited Bex CC BY-SA 3.0
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Oct 11, 2011 at 15:41 comment added Bex I have amended my bearings, it was a diamond.. it's now square
Oct 11, 2011 at 15:41 history edited Bex CC BY-SA 3.0
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Oct 11, 2011 at 15:21 comment added Ian Turton that won't be a square.
Oct 11, 2011 at 15:08 history answered Bex CC BY-SA 3.0