Timeline for Polarity of Slope raster for use in Multi Criteria Evalution
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 4, 2016 at 20:17 | comment | added | If you do not know- just GIS | perfect no problem | |
| Jan 4, 2016 at 20:14 | vote | accept | Steven | ||
| Jan 4, 2016 at 20:11 | comment | added | Steven | Thanks, I reclassed to 10 classes and did Float("Reclass_Slope" - 1) / (10 - 1), which gave me this i.imgur.com/ZgwuVbg.png. Pretty sure this is correct now, many thanks. | |
| Jan 4, 2016 at 19:47 | comment | added | If you do not know- just GIS | I would use reclassify tool 0 to 10 | |
| Jan 4, 2016 at 18:58 | comment | added | Steven | Just seen your last comment, still unclear as to what you mean. Is this in raster calculator or reclassify tool? | |
| Jan 4, 2016 at 18:55 | comment | added | Steven | Using the identify tool steep sloping areas give me smaller values than flat areas and all range between 0-1, so i presume its correct. | |
| Jan 4, 2016 at 18:55 | comment | added | If you do not know- just GIS | so reclassify say 0 to 10 then multiply by .1 (float as well) then you have a 0 to 1 scale. | |
| Jan 4, 2016 at 18:38 | comment | added | Steven | Sorry I dont understand, what do i need to multiply by .1? Thanks again | |
| Jan 4, 2016 at 16:57 | comment | added | If you do not know- just GIS | that is fine, just change your high end in the reclass to 9999 it is missing your high value. it will be fine, just float the output and multiply by .1 or similar. | |
| Jan 4, 2016 at 12:53 | comment | added | Steven | I've tried this in Raster Calculator (("StandardSlope" - 0.999999) * -1) + 0) and got this which is correct altough it still doesnt range from 0 - 1 like the rest of my layers.i.imgur.com/cwwcutn.jpg Would this still work correctly in an MCE? Thanks | |
| Jan 4, 2016 at 11:58 | comment | added | Steven | That last image is after i standardised the layer, which is nearly correct however it is still the wrong polarity and multiplying by -1 gives a high value of -0 and a low value of -0.9999. | |
| Jan 4, 2016 at 11:51 | comment | added | Steven | Thanks, i tried that and got this i.imgur.com/tsPRSHl.jpg and this i.imgur.com/BKrALUP.jpg and then tried to standardise it and got this which still seems to be incorrect as the whole layer is now classed as '0' i.imgur.com/EwdFrIF.jpg. As per this post (gis.stackexchange.com/questions/174412/…) the original Slope raster is in floating point and after that reclassification it is now integer type. I therefore did (100*(“Slope” – 0)) / (36.58 – 0) and got this i.imgur.com/MaN2jlD.jpg | |
| Jan 4, 2016 at 0:21 | history | answered | If you do not know- just GIS | CC BY-SA 3.0 |
