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Kersten
Kersten
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The above solution, at least at time of writing, is somewhat incorrect. The format to substitute is actually :

!1i{z}!2i{x}!3i{y}!

2i=x2i=x and 3i=y3i=y. Not sure if the API has changed recently, but that seems to be what it is now.

The above solution, at least at time of writing, is somewhat incorrect. The format to substitute is actually :

!1i{z}!2i{x}!3i{y}!

2i=x and 3i=y. Not sure if the API has changed recently, but that seems to be what it is now.

The above solution, at least at time of writing, is somewhat incorrect. The format to substitute is actually :

!1i{z}!2i{x}!3i{y}!

2i=x and 3i=y. Not sure if the API has changed recently, but that seems to be what it is now.

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frugardc
frugardc
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The above solution, at least at time of writing, is somewhat incorrect. The format to substitute is actually :

!1i{z}!2i{x}!3i{y}!

2i=x and 3i=y. Not sure if the API has changed recently, but that seems to be what it is now.