Timeline for Distance to inland boundaries rather than coasline
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Nov 8, 2016 at 15:11 | comment | added | Knightshound | Please don't add "thank you" as an answer. Once you have sufficient reputation, you will be able to vote up questions and answers that you found helpful. - From Review | |
| Nov 8, 2016 at 14:51 | comment | added | albatros | Thank you very much for your response: I think this method should work. But when I run the Symettrical Difference command, I run in the following error : "global name 'QgsWKBTypes' is not defined See log for more details". I am working on the 2.18.0 version. How can fix it ? Is there another command to do the same if there is a bug on that command. Best regards ! | |
| Nov 7, 2016 at 22:40 | answer | added | user6072577 | timeline score: 2 | |
| S Nov 7, 2016 at 21:21 | history | suggested | whyzar | CC BY-SA 3.0 |
corrected spelling, fixed grammar, improved formatting.
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| Nov 7, 2016 at 21:09 | review | Suggested edits | |||
| S Nov 7, 2016 at 21:21 | |||||
| Nov 7, 2016 at 17:31 | comment | added | albatros | Thank for your response. But this approach suppose distinguishing between country cases right ( coastal and inland) ? And I am not sure the v_distance funcition is that much sophisticated. I am really new to Qgis so simple steps might quickly be cumbersome for me. How would you please do that ? | |
| Nov 7, 2016 at 16:56 | comment | added | user1462 | An insane suggestion: compute the minimum distance to borders of other countries. Presumably, the border you seek is also a border of another country. | |
| Nov 7, 2016 at 16:31 | review | First posts | |||
| Nov 7, 2016 at 16:42 | |||||
| Nov 7, 2016 at 16:27 | history | asked | albatros | CC BY-SA 3.0 |