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Nov 18, 2022 at 21:38 comment added RyanKDalton @DPSSpatial_BoycottingGISSE This only works because you are choosing a single neighborhood polygon from "n", which is essentially removing the pair-wise comparison of multiple features in the source to multiple features in the destination
Jan 5, 2018 at 17:16 comment added Evan Carroll Here is an example WITH t(x) AS (VALUES (1),(2),(3),(4)) SELECT * FROM t AS t1 JOIN t AS t2 ON NOT t1.x = t2.x;
Jan 5, 2018 at 17:10 comment added Evan Carroll This is what you want: gis.stackexchange.com/a/136177/6052
Jan 5, 2018 at 17:07 comment added Evan Carroll It means if you're not just getting 1 denver.address, you're getting one for every not-matching denver.neighborhood.
Jan 5, 2018 at 16:46 comment added Inactivated Account @EvanCarroll what does that mean?
Jan 3, 2018 at 2:05 comment added Evan Carroll This is actually a pretty bad idea because you're getting the cartesian product
Sep 6, 2017 at 18:55 history edited Inactivated Account CC BY-SA 3.0
added 128 characters in body
Jan 26, 2017 at 18:22 comment added Inactivated Account @NateWanner good to know! I can't believe how easy and fast that is!!!
Jan 26, 2017 at 17:57 comment added Nate Wanner Also worked for "NOT ST_Within". My query completed in ~30.0 seconds for both the NOT ST_Within and using an outer join then checking for Null on the right side, so there doesn't seem to be any performance hit. Thanks!
Jan 20, 2017 at 21:54 history answered Inactivated Account CC BY-SA 3.0