Timeline for Comparing raster layers and finding the combined minimum
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 23, 2017 at 18:49 | answer | added | Robert Hijmans | timeline score: 1 | |
| Nov 23, 2017 at 15:25 | history | edited | HDunn | CC BY-SA 3.0 |
formatting and clarity
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| Nov 23, 2017 at 15:22 | vote | accept | uybfi | ||
| Nov 23, 2017 at 15:22 | comment | added | HDunn | I've edited my comments to an answer | |
| Nov 23, 2017 at 15:22 | answer | added | HDunn | timeline score: 2 | |
| Nov 23, 2017 at 15:09 | comment | added | uybfi | thank you! one last question: how can i "upvote" your answer or mark as the best answer? the help shows i can mark an answer, but i dont see any options here. | |
| Nov 23, 2017 at 15:00 | comment | added | HDunn | yes, either by sum or by multiplication (then have a range from 0.01). you can use r.rescale for that purpose. grass.osgeo.org/grass64/manuals/r.rescale.html | |
| Nov 23, 2017 at 14:36 | comment | added | uybfi | just so make sure i understand you: you suggest converting the absolute value of each pixel into a relative value, to make them comparable and thus making it possible to use r.series to get a pixel value that essentially says: "this pixel has a value of 1/2x" by summing up x of each layer? english is not my first language and the normalization i know is to get rid of redudant values in a database. Also im interested in how this works so ill be very thankful for a more in depth response. but im already thankful for your answer and will read up on what you suggested. | |
| Nov 23, 2017 at 14:24 | comment | added | HDunn | you can normalize each raster from 0 to 1 and then use r.series to calculate the sum. for each pixel. | |
| Nov 23, 2017 at 14:18 | review | First posts | |||
| Nov 23, 2017 at 14:23 | |||||
| Nov 23, 2017 at 14:14 | history | asked | uybfi | CC BY-SA 3.0 |