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Nov 21, 2018 at 12:30 vote accept Andre Silva
Nov 21, 2018 at 12:30 comment added Andre Silva You nailed it. vgm takes the exponential model as C(h) = (σ² - a)*exp(-|h|/r) (or S(h) = a + (σ² - a)*(1-exp(-[h]/r)), i.e., 'range' is approximate one third from the dist where the variogram curve flattens. See gis.stackexchange.com/questions/153931/…. Thank you.
Nov 21, 2018 at 8:41 history answered Spacedman CC BY-SA 4.0