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Mar 16, 2019 at 18:16 comment added Andre Silva @Joy, if Berend's answer helped you find the solution, it means it was useful. You can upvote it. See: gis.stackexchange.com/help/someone-answers. Tks.
Feb 28, 2019 at 12:28 comment added Joy @ Berend sorry for the confusion, my question was not that well formulated, what I meant to say is whether I could apply the properties of the polygon function to the graphic object and I managed to do that with the hint you gave (geometry.type) and instead I used geometry.centroid.latitude. Thank you very much for the hint
Feb 28, 2019 at 12:23 comment added Berend I'm not sure I understand that last comment ('Do you know by any change how I can use the graph object in the Polygon function'), could you explain what you want exactly? Or even better, post a new question?
Feb 28, 2019 at 9:17 comment added Berend That isn't relevant, a featurelayer is based on features, which are of type graphic.
Feb 28, 2019 at 9:06 comment added Joy Hi Berend, thank for the explanation, unfortunately my layer is a feature layer, I forgot to mention it. But thanks for explaining in case when the object was graphic object.
Feb 28, 2019 at 8:51 history answered Berend CC BY-SA 4.0