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S Oct 22, 2022 at 13:14 history suggested Padmanabha CC BY-SA 4.0
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Oct 22, 2022 at 12:05 review Suggested edits
S Oct 22, 2022 at 13:14
Sep 14, 2021 at 2:56 history edited PolyGeo CC BY-SA 4.0
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May 13, 2020 at 20:00 comment added FelixIP Not clear how many cells total under this buffers. So split your buffers into non overlapping groups gis.stackexchange.com/questions/317923/… and repeat raster calculations n times. Each set will have few steps; euclidean distance from relevant points, max value at center from buffer, max/d/d, fill gap at points. This is output from 1st group. Repeat and summarise.
May 13, 2020 at 7:06 comment added Mike So one buffer has an area of more than 5000 m^2. The radius can range between 40 to 70 meters or so. Therefore if you have a cell size of 1 than the amount of cells equal the area. However, if that is too much then the cell size could be enlarged?
May 12, 2020 at 21:00 history tweeted twitter.com/StackGIS/status/1260313836067979269
May 12, 2020 at 20:59 comment added FelixIP There are raster and vector solutions depending on a total number of cells inside buffers. What is your estimate? Are we talking 100s k?
May 12, 2020 at 20:52 comment added Mike @FelixIP Yes the values at the source point are the same and therefore the buffers are identical at first.
May 12, 2020 at 20:51 comment added FelixIP Are values at source points equal each other? If not buffers should be different.
May 12, 2020 at 19:23 comment added Hornbydd Have a look at the euclidean distance tool that will create your distance pixels that you would feed into your luminosity equation, no python required.
May 12, 2020 at 18:15 review First posts
May 12, 2020 at 18:23
May 12, 2020 at 18:15 history asked Mike CC BY-SA 4.0