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Aug 25, 2023 at 5:31 vote accept Marin Marian
Aug 14, 2023 at 9:42 history edited Kadir Şahbaz CC BY-SA 4.0
added 1 character in body
Aug 12, 2023 at 21:34 answer added Marin Marian timeline score: 0
Aug 12, 2023 at 12:18 comment added Ben W Because you are using processing.run() calls as child algorithms, their outputs will be map layer id strings, not QgsVectorLayers, see this answer. You can get a map layer object like: motorway_link_lyr = context.getMapLayer(results['Motorway_link_osm']).
Aug 11, 2023 at 18:07 history asked Marin Marian CC BY-SA 4.0