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Jun 21 at 19:15 history became hot network question
Jun 21 at 14:39 history edited BKS CC BY-SA 4.0
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Jun 21 at 14:37 comment added BKS Thank you @bera. I tried this but my problem is I do not know how many columns I will have in my table. My table will have one grouping variable field and it can have any number of numeric fields> i cannot find a suitable sql query to ask select groupingfield, sum(all_columns) from mylayer group by grouping_field .
Jun 21 at 13:44 comment added Bera It is possible to create a virtual layer using SQL, like: SELECT groupfield1, groupfield2, sum(col1), sum(col2), sum(col3) FROM mylayer GROUP BY groupfield1, groupfield2
Jun 21 at 13:38 comment added Babel Adding multiple fields to Field(s) with categories is possibly by default, I don't know why you ask about that. Did you have a close look at how this tool works? To calculat multiple statistics for several different fields at once (Field to calculate statistics on), use batch mode: see my answer.
Jun 21 at 13:34 answer added Babel timeline score: 2
Jun 21 at 13:31 comment added Erik So you could run sum() for each column?
Jun 21 at 12:20 comment added BKS I edited the question. @Erik, sum works for one field. I wish to summarize multiple fields. In fact I wish to total all columns except the grouping variable.
S Jun 21 at 12:18 history edited BKS CC BY-SA 4.0
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Jun 21 at 12:04 review Close votes
Jul 8 at 3:04
Jun 21 at 11:54 review Suggested edits
S Jun 21 at 12:18
Jun 21 at 11:42 comment added Babel Sorry, your question is not clear to me. What is your problem? You have one or two fields for grouping in the attribute table? And what exactly does not work in statistics by category tool? Please use the right terminology of the tool, otherwise we don't understand you: in the tool, you have Field to calculate statistics on and Field(s) with categories: so what are you speaking about? Please edit your initial question, otherwise it risks to be closed.
Jun 21 at 11:25 history edited Vince CC BY-SA 4.0
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Jun 21 at 11:22 comment added Erik Have you tried the sum() expression?
S Jun 21 at 11:12 review First questions
Jun 21 at 13:29
S Jun 21 at 11:12 history asked BKS CC BY-SA 4.0