Converting *.lyr file to shapefile or raster using ArcPy?

Question

I am using ArcGIS Desktop 10 and Python 2.6.5.

i have created a "test.lyr" file, now i want to convert it either to shape file or raster file. i have created the "test.lyr" from "test0.tif" and added symbology from "test0.lyr" files as follows.

 arcpy.MakeRasterLayer_management(tifFile,tmpFile,"#","","#")
 arcpy.SaveToLayerFile_management(tmpFile,curFile)
 arcpy.ApplySymbologyFromLayer_management(curFile,symbologyLayer)

the curFile in the above code is the test.lyr file obtained.

Can anyone show how to convert it to "test1.shp" or "test1.tif" file using arcpy?

Answer 1

You can use the Feature Class to Shapefile geoprocessing tool to convert a lyr to a shp (see code example below).

BASEMAP_LOADER_Counties_lyr = "C:\\Temp\\BASEMAP.LOADER.Counties.lyr"
Temp__2_ = "C:\\Temp"

# Process: Feature Class To Shapefile (multiple)...
gp.FeatureClassToShapefile_conversion("C:\\Temp\\BASEMAP.LOADER.Counties.lyr", Temp__2_)

And you can use the Feature to Raster tool to convert a lyr to raster (see code sample below).

Feature_2_tif = "C:\\Temp\\Feature_2.tif"
BASEMAP_LOADER_Counties_lyr__2_ = "C:\\Temp\\BASEMAP.LOADER.Counties.lyr"

# Process: Feature to Raster...
gp.FeatureToRaster_conversion(BASEMAP_LOADER_Counties_lyr__2_, "OBJECTID", Feature_2_tif, "4832.40368")

Answer 2

I converted a polygon KML to a layer by KMLtoLayer in ArcGIS 10.5... I only could convert this layer to shp by the following procedure:

# Final shp path (Example)
shape_path = r'E:\40\00_SOL_PONTUAIS\20200922_Rangel_Consalter_REGULADOR\SHP\teste.shp'

# setting workspace
arcpy.env.workspace = r'D:\' # folder where u saved your layer

# Converting to shapefile
arcpy.FeatureToPolygon_management(r'LAYER_NAME\Polygons',
                                  shape_path, '#', 'ATTRIBUTES', '#')
### OBS --> replace 'LAYER_NAME' be the name of your layer name