1

I am trying to accomplish this task: https://stackoverflow.com/questions/15851568/how-to-get-the-last-part-of-a-string-before-a-certain-character within the Field Calculator.

I have the below but cannot get it to run.

What am I missing?

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4

You are using the syntax from the question, not the answer. Also, the pre-logic code for Python can't reference field names. You also might want to check out .rpartition().

You shouldn't have to use pre-logic at all:

Sector = !FolderPath!.rsplit("/")[0]

But if you did want to use pre-logic, here's how to do it:

def sect(field):
   return field.rsplit("/")[0]

Sector = sect(!FolderPath!)

With that being said, if you are splitting pathnames, I encourage you to check out os.path.split() instead (Python docs). It's a lot simpler to deal with pathnames this way and is the more pythonic route.

Edit for slicing:

a = [1, "fish", 2, "fish", "red fish", "blue fish"]
a[0] -> 1
a[1] -> "fish"
a[2] -> 2
a[-1] -> "blue fish"
a[0:2] -> [1, "fish"]
  • thanks for clarifying my overcomplication. Your suggestions works, but I need it to run from the end of the string. I added a colon before the 0 but that does not work. – mikeLdub Jul 28 '14 at 16:24
  • @mikeLdub Ahh, I've updated my code to reflect that. – Paul Jul 28 '14 at 16:25
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    Or os.path.dirname()/os.path.basename() if you're only interested in the head/tail of the path, rather than both parts in a tuple. – nmpeterson Jul 28 '14 at 16:25
  • @nmpeterson, yes good point! Definitely the better option if you only need one, which OP probably does. I assume he wants the head, but I'm not sure. – Paul Jul 28 '14 at 16:28
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    @mikeLdub, you need to look up slicing syntax. The number inside the brackets refers to which number in the list to return. I've edited my post to give a brief overview of slicing. So, you'll probably want to change [0] to [1] – Paul Jul 28 '14 at 16:34

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