1

I have a geodatabase with a given number of polygon features. I would like to generate a layer (V) that displays the number of overlapping polygons at any given (x,y) location spanned by my polygons. For example, if at (x1,y1) I have two overlapping polygons my V(x1,y1)=2, if I have no polygons at (x2,y2) then V(x2,y2)=0, and so on. What is the easiest way to build this map? I am currently reviewing join and merge tools to see how I can make this work.

1

I would loop over each polygon and first create a binary raster where the cell value is one inside the polygon, and zero outside, and then use map algebra to add it to a total raster.

Unless you have a trivial number of polygons, you will probably want to write an arcpy script to do this.

1
  • there must be an easier way using already built in tools? another post gis.stackexchange.com/questions/51929/… describes this but the dissolve function is not adding up the overlapping polygons. – val Nov 8 '14 at 1:16
1

I know this is an older post but I had a similar problem and found this tool http://www.arcgis.com/home/item.html?id=1dd4a6832b3d40b494dbf8521cc5134c, was the easiest solution.

0

using union and dissolve i was able to get it to work, the key for me was to select the right Dissolve_Field to Count over in the Statistics Field (i.e. both fields match and I used "shape_Area" as the unique indentifier). Thanks for the comments! This post was most helpful for me: Counting and rasterizing polygon overlaps in ArcGIS Desktop?

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.