Knowing the center of rotation, start and end angles, inner an outer radius, how can this be achieved with MapBasic
You can create a function like this:
Function CreateAnnulusSector( ByVal oCenterPoint As Object
, ByVal fInnerRadius As Float 'in meters
, ByVal fOuterRadius As Float 'in meters
, ByVal fStartAngle As Float
, ByVal fEndAngle As Float
, ByVal nResolution As Integer
) As Object
Dim oSector, oCutter As Object
Dim fAngle, fRotatedAngle, fX, fY, fDistance As Float
Dim i As Integer
CreateAnnulusSector = oCenterPoint
'**Create concentric circle
oSector = CartesianBuffer(oCenterPoint, nResolution, fOuterRadius, "m")
oSector = Erase(oSector, CartesianBuffer(oCenterPoint, nResolution, fInnerRadius, "m"))
'**Find center coordinates
fX = CentroidX(oCenterPoint)
fY = CentroidY(oCenterPoint)
'**Calculate distance for cutter object
fDistance = 3 * fOuterRadius
'**Create cutter object
Create Pline Into Variable oCutter
1 (fX, fY)
Alter Object oCutter
Node Add (fX + fDistance, fY)
fRotatedAngle = fEndAngle - fStartAngle
If fRotatedAngle > 360 Then
fRotatedAngle = fRotatedAngle - 360
End If
If fRotatedAngle < 0 Then
fRotatedAngle = fRotatedAngle + 360
End If
For i = 4 To 1 Step -1
If (i * 90) < fRotatedAngle Then
Alter Object oCutter
Node Add ( fX + ((Cos(fRotatedAngle * DEG_2_RAD)) * fDistance)
, fY + ((Sin(fRotatedAngle * DEG_2_RAD)) * fDistance))
Exit For
Else
Alter Object oCutter
Node Add ( fX + ((Cos((i * 90) * DEG_2_RAD)) * fDistance)
, fY + ((Sin((i * 90) * DEG_2_RAD)) * fDistance))
End If
Next
'**Rotating cutter object to start angle
oCutter = RotateAtPoint(oCutter, fStartAngle, oCenterPoint)
'**Convert cutter polyline to a polygon
oCutter = ConvertToRegion(oCutter)
'**Erase the concentric circle with the cutter object
oSector = Erase(oSector, oCutter)
CreateAnnulusSector = oSector
End Function
Clever mathematician could surely find an easier way to deal with the angles.
I use the way MapInfo Pro is working with angles here. The start from the East and move counter clockwise.
Also note that I'm using CartesianBuffer and some other logic that require you to work with a projected coordinate system - latitude/longitude will give you some issues.
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Peter, Thanks for your answer. I'll give it a go and will let you know – Annulus Nov 20 '14 at 18:42