I am working on a project that uses OpenLayers (version 2.14)to display a Bing layer(GeoJSON format), I have no problem reading the GeoJSON and display features, but I want to select a feature programmatically, for example, there is a table displaying all the features attributes(GeoJSON format.sample:

{"type": "FeatureCollection", "features": [ {"type":"Feature","properties":{},"geometry":{"type":"Point","coordinates":[-7923751.4232522,5233536.7371399]},"crs":{"type":"name","properties":{"name":"urn:ogc:def:crs:OGC:1.3:CRS84"}}} ], }

), when I click a row from the table, I want to select or highlight a specific feature on the map using the GEOJSON data in that row.

How can I do that?

1 Answer 1


You could use the method "getFeaturesByAttribute"

or iterate through all features:

 for(var i = 0; i < yourgeojsonlayer.features.length; i++) { 
    if(yourgeojsonlayer.features[i].attributes.searchedAttribute == 'searchedValue')
     { selectFeatureControl.select(yourgeojsonlayer.features[i]); break; } 

Ps: makes necessary to create a select control first and assign the variable name you use in the for loop (here selectFeatureControl)

I just wrote down a quick example here: http://jsfiddle.net/expedio/sh9wv4m7/

  • Imagine ,i clicked on table and get Following geojson : var featurejson= {"type": "FeatureCollection", "features": [ {"type":"Feature","properties":{},"geometry":{"type":"Point","coordinates":[-7923751.4232522,5233536.7371399]},"crs":{"type":"name","properties":{"name":"urn:ogc:def:crs:OGC:1.3:CRS84"}}} ], };
    – Ismayil
    Commented Jan 27, 2015 at 7:54
  • vlayer = new OpenLayers.Layer.Vector("Editable"); map.addLayer(vlayer); geojson_format = new OpenLayers.Format.GeoJSON(); geojson_format.ignoreExtraDims = true; var ft = new OpenLayers.Feature.Vector(geojson_format.read(featuredata),{scientific_name:'hydro'}); vlayer.addFeatures([ft]); var features = vlayer.features; var selectControl = new OpenLayers.Control.SelectFeature(vlayer, {multiple: true,toggle: false}); window.map.addControl(selectControl); selectControl.activate();
    – Ismayil
    Commented Jan 27, 2015 at 8:05
  • selectFeature.select(vlayer.getFeatureBy('scientific_name', 'hydro'));
    – Ismayil
    Commented Jan 27, 2015 at 8:05
  • I do that,but it is not working.Can you help me ,how can I do that with "getFeatureBy" or "getFeaturesByAttribute"
    – Ismayil
    Commented Jan 27, 2015 at 8:08
  • 1
    just post your code here at stackexchange or jsfilldle so others can also help you or benefit from an answer that's found
    – Thomas B
    Commented Jan 27, 2015 at 10:15

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.