1

I am using OpenLayers 2.11 from here http://cdnjs.com/libraries/openlayers and trying to display WMS layer. It is in 3301 projection so projection is defined as follows:

proj4.defs("EPSG:3301","+proj=lcc +lat_1=59.33333333333334 +lat_2=58 +lat_0=57.51755393055556 +lon_0=24 +x_0=500000 +y_0=6375000 +ellps=GRS80 +towgs84=0,0,0,0,0,0,0 +units=m +no_defs");
var projection = new OpenLayers.Projection('EPSG:3301');

and WMS layer and map like this:

 var bounds = new OpenLayers.Bounds(
            370753.1145, 6382922.7769, 739245.6000, 6624811.0577
    );
    var options = {
        maxExtent: bounds,
        maxResolution: 2601.4538070271437,
        projection:projection,
        units: 'm'
    };
    map = new OpenLayers.Map('map', options);
var base  = new OpenLayers.Layer.WMS("Maa/ameti aluskaart",
            "http://kaart.maaamet.ee/wms/alus?",{layers: 'MA-ALUS',
                version: '1.1.1' ,'srs':projection});
map.addLayer(base);

But there are no request at all with 2.11 version of OpenLayers. With OpenLayers 2.12 it is shown, but I am interesting in how to show WMS in older OpenLayers 2.11 version.

1

just add this js from the cdn:

https://cdnjs.cloudflare.com/ajax/libs/proj4js/1.1.0/proj4js-combined.js

and use following code:

var projection= new OpenLayers.Projection("EPSG:3301");
var bounds = new OpenLayers.Bounds(
            370753.1145, 6382922.7769, 739245.6000, 6624811.0577
    );
    var options = {
        maxExtent: bounds,
        maxResolution: 2601.4538070271437,
        projection:projection,
        units: 'm'
    };
    map = new OpenLayers.Map('map', options);
var base  = new OpenLayers.Layer.WMS("Maa/ameti aluskaart",
            "http://kaart.maaamet.ee/wms/alus?",{layers: 'MA-ALUS',
                version: '1.1.1' ,'srs':projection});
map.addLayer(base);
map.setCenter(new OpenLayers.LonLat(25.567422, 58.885704).transform(new OpenLayers.Projection("EPSG:4326"),projection),2);

see this example: http://jsfiddle.net/expedio/ccp9L6gv/

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.