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Have spent some time on generalizing some datasets and got puzzled by the algorithm used by the Integrate GP tool.

I have two points in a file geodatabase of 10.3 version, those points are located on a certain distance from each other. I run the Integrate tool (tried both inside and outside the editing session). The feature class is stored in a projected coordinate system (specifically, the WGS_1984_Web_Mercator_Auxiliary_Sphere). I run the Integrate tool on this feature class with the cluster tolerance = 1000m.

I cannot comprehend how the cluster tolerance is used. I've added a scale bar while in Layout mode for illustration purposes. Here points will be integrated when the distance between them = ~2300m.

enter image description here

They stop collapsing into one feature in between when the distance gets larger than ~2800m. Any value smaller than that will move both points into a position that is right between them (i.e., they get integrated). enter image description here

So, I could see two ways the cluster tolerance is used:

  • if the distance between the two points is smaller than the cluster tolerance, they will be moved into a common central position; doesn't seem to work for me - they get integrated when distance between them > 1000m.
  • if the circles around the points (with radius=cluster tolerance) intersect, they will be moved into a common central position (then they should be integrated if the distance between points < 2000m, which again is not the case.

Can anyone explain how does the Integrate tool work in terms of cluster tolerance, because from my tests it doesn't make sense.

I am on ArcGIS 10.3, but I've tested on 10.2 and got the same behaviour.

  • There is some information on clusters and tolerances on both resources.arcgis.com/en/help/main/10.1/index.html#//… and resources.arcgis.com/en/help/main/10.1/index.html#//… you may find helpful. – Chris W Mar 11 '15 at 4:30
  • @ChrisW, a great page, shame I couldn't find it myself :) if no one will post any valid answer in a couple of days, please do wrap your comment into an answer which I will gladly accept. – Alex Tereshenkov Mar 11 '15 at 5:56
  • I think it would probably be better if you formulate the answer, as while I found the resource and read it, I still couldn't quite put the pieces together - it seemed to me that with 1000m tolerance anything from about 1400m or closer would be integrated, but you're getting 2,800. I'm not sure I could make a legitimate question answer since I don't fully understand what I linked to. :) – Chris W Mar 11 '15 at 21:47
  • @AlexTereshenkov Is there any chance to you can post a brief self-answer to close off this one? – PolyGeo Jan 14 '17 at 7:58

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