I need the name of each layer in an .msd, but I could not find support using arcpy (ArcGIS 10.0). Is there a method I missed?

In the current workflow, since I am publishing the document, I use the REST service:

descriptionUrl = url + "/ArcGIS/rest/services/" + mapServer + "/MapServer?f=json"  
restResponseFp = urllib.urlopen(descriptionUrl)
mapDescription =json.load(restResponseFp)
layerNames = [str(layer["name"]) for layer in mapDescription["layers"]]

1 Answer 1

import zipfile
from xml.etree.cElementTree import iterparse

zz = zipfile.ZipFile('C:\\Temp\\Untitled.msd')

serviceNames = []
for name in zz.namelist():
    if name == "DocumentInfo.xml" or name == "layers/layers.xml":
        for _event, elem in iterparse(zz.open(name)):
            if elem.tag == "Name":

Files associated with layers are named like this: layers/featureclassname.xml

Long service names are truncated to make the file name, so we must parse the file contents to handle all cases.

  • Thanks! Actually, I notice that since my service names are very long, the xml file name is truncated. Each file associated with a layer must be parsed for the "Name" element to reliably handle long service names. Commented Nov 1, 2011 at 5:28
  • @theJones is there any way to get the service from the DocumentInfo.xml? Do you know any property that can print the service name? Commented Aug 17, 2017 at 23:04

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.