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I'm new to Python/VB Script and am needing some help. I have tried several different If/Then statements but can't seem to get it straight. I am hoping for some help. I have 3 fields. ZONING, SQFeet_1, and Buildout. Depending on the Value of the ZONING field, will depend on what formula I need to use. For instance, if ZONING = RS6 then I need to use the formula (SQFeet_1/6000*.80) or if ZONING = SP then I need to use the formula (SQFeet_1/2000*.80), etc... How would I write the IF/Then statement to get the results? Or would I need to use a different statement?

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  • If [ZONING] = 'RS6': Then (SQFeet_1/6000*.80) Elif [ZONING] = 'SP': Then (SQFeet_1/2000*.80) – Kevin Cross Mar 28 '16 at 20:10
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    You should add that code to your question, users here like to see the effort you've put in so far. – Dan C Mar 28 '16 at 20:20
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Best go is use of dictionary:

def getDivider(A,B):
    aDict={'RS6':6000,'SP':2000}
    if A in aDict:  return B/aDict[A]*0.8
    return -1

====================================== 

getDivider(!ZONING!,!SQFeet_1!)

Update following @Paul suggestion:

def getDivider(A,B):
  aDict={'RS6':6000,'SP':2000}
  return B/aDict.get(A,0)*0.8
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  • why should the function return -1? – ziggy Mar 28 '16 at 19:37
  • To answer this read line above – FelixIP Mar 28 '16 at 19:48
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    A different approach would be return B/aDict.get(A, 0)*0.8 where 0 is a value you want returned when a value can't be found in the dict (aka, the default value). No need to check if the key is present. – Paul Mar 28 '16 at 21:47
  • @Paul very nice, will make it even shorter – FelixIP Mar 28 '16 at 22:13
  • Thanks guys, I'm going to try this out today and will get back with ya'll! – Kevin Cross Mar 29 '16 at 12:53

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