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I have a string field named CHESS2016_N94S_FL1_C__20160407230029.562GMT_COLOR-8-BIT.JPG and I would like to select characters 16-18 to populate a new field. I've been trying to use the field calculator index function in ArcMap but have only been getting errors.

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    VB syntax mid(field,16,3) – FelixIP May 15 '16 at 0:49
  • I think it is much nicer and versatile in Python, i.e. field [16:19] – fatih_dur May 15 '16 at 2:46
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As commented by @FelixIP this can be done in:

VB syntax mid(field,16,3)

and as commented by @faith_dur:

it is much nicer and versatile in Python, i.e. field [16:19]

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