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About 71% of the Earth's surface is covered with water and the remaining 29% is landmass*. If you could theoretically cut the planet in half, with the objective of producing a half with the most landmass possible (and another with the most water possible), where would the cut be? More specifically, where would the centers (in the surface) of both halves be located?

closed as off-topic by Vince, Chad Cooper, Mapperz Jun 21 '16 at 15:38

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    I wonder if this type of question is more suited for EarthScienceStackExchange :) – Joseph Jun 21 '16 at 12:09
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    This is easy enough to model using GIS, but as written, this is more of a geography trivial question. GIS SE is about focused GIS questions. – Vince Jun 21 '16 at 13:06
  • @Joseph I actually asked there first, but their answers weren't precise at all. earthscience.stackexchange.com/q/8226/6180 – Gabe12 Jun 21 '16 at 13:09
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    @Gabe12 - Glad to see you did! But you did only ask it 12 hours ago (as of this comment). You should probably wait atleast a day to see if others answer your question. Also, cross posting is discouraged in Stack Exchange =) – Joseph Jun 21 '16 at 13:14
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    If you're not willing to do the work to identify the location identified by that perfectly reasonable answer, why would you expect us to do it for you? – Vince Jun 21 '16 at 13:25
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A quick google search yielded this result which states in the paragraph before "Continents and Oceans" that 'this land hemisphere is centered on Western Europe.' You could validate this and get the precise location with functions in PostGIS by finding the centroid of a polygon (landmass). Then you can do some math to find the cut line based on the centroid.

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