ArcPy SearchCursors - Compare rows in attribute table - cursor.next() function

Question

I'm new to ArcPy and have a question about ArcPy search cursors. I need to compare the current row of a point shapefile to the previous row for string field "Cat" and IF they are equal then I want to print the FID, ELSE print "NoMatch".

Code and data found below. The issue is cursor.next() seems to skip a row perhaps? The output is 1, 3, 5, 7, 9 when it should be 1, 2, 3, 5, 6, 8, 9, 10 (note 4 and 7 should not print because the "Cat" field value does match the previous). Also not sure why 7 was returned in the result.

DATA

FID Cat POINT_X POINT_Y
0 Sand 619557.6 4843930.0 
1 Sand 619515.4 4843900.5
2 Sand 619513.8 4843899.7
3 Sand 619512.6 4843898.6
4 Gravel 619511.3 4843897.5
5 Gravel 619508.8 4843895.5
6 Gravel 619507.5 4843894.5
7 Sand 619495.5 4843883.5
8 Sand 619486.1 4843876.3
9 Sand 619484.1 4843875.3
10 Sand 619476.0 4843870.2

CODE

import arcpy 
shp = "C:\TEST.shp" 
cursor = arcpy.SearchCursor(shp)
for row in cursor:
    rowCur = row
    rowPost = cursor.next()

    if rowPost.getValue("Cat")==rowCur.getValue("Cat"):
        print (row.getValue("FID"))
    else:
        print "NoMatch"

Answer 1

Try something along these lines (warning: this is untested).

import arcpy 
shp = "C:/TEST.shp" 
cursor = arcpy.SearchCursor(shp)
previousValue = ""
for row in cursor:
    rowCur = row
    # rowPost = cursor.next()

    if row.getValue("Cat")== previousValue:
        print (row.getValue("FID"))
    else:
        print "NoMatch"
    previousValue = row.getValue("Cat")