I have a large data set of points which has the field 'Name'.
Some of the points have an attribute such as 'Slope >40%' or 'Grade 10-30%' for example.
I would like to use Select By Attributes and the LIKE operator to select all points which have a % within the attribute.
I've tried different combinations such as:
WHERE NAME LIKE '%[%]%'
But no luck on trying several combinations...