I want to extract time series from a variable in a 3D (lon,lat,time) netcdf file at specific lon/lat points. The raster is a nc file where:

cell: 1.5°×1.5°
time step: 1 month
lat extension: (0.75,89.25,1.5)
lon extension: (0.75,359.25,1.5)
time: (201001,205012)
step scale: cell center 

I have a point shapefile (lat/lon) where a point is (108.3°,58.6°). I just want to extract the cell values of the whole time steps in where points located. Are there directly method to carry out it?

I think a way that round the points number according to lat/lon step: changing the P lat/long to cell lat/lon where point located. For instance, P(108.3°, 58.6°) is in cell (108°,60°) because scale step is 1.5°. Now, the question is how to change P(108.3°,58.6°) to cell(108°,60°) used to slice .nc file.

1 Answer 1


So you have 3D data (lon,lat,time) in a netcdf file and you want to extract a time-series as a specific location in Python, right?

Here's one way using netCDF4: http://nbviewer.jupyter.org/gist/rsignell-usgs/4113653

But it's way easier using Xarray: http://nbviewer.jupyter.org/gist/rsignell-usgs/e032db75e748cf5922d38d8be9e0ecef

import xarray as xr

fname = 'http://thredds.ucar.edu/thredds/dodsC/grib/NCEP/GFS/Global_onedeg/Best'  # Remote OPeNDAP Dataset 
#fname = 'my_raster_time_series_data.nc'   # Local NetCDF file

ds = xr.open_dataset(fname)
dsloc = ds.sel(lon=230.5,lat=55.0,method='nearest')


enter image description here


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.