I have a model in ArcGIS 10.3.1 which splits a large (> 1,000) polygons by a road network (as polylines). Currently, I am using Xtools' Split Polygons, but this would require an end-user to have a copy of XTools which I need to not be a requirement. I have found this tool, but, when I have tried to use it, it takes a very long time to run (much longer than the XTools equivalent). Does anyone know of any other tools which do the same thing, but are not locked behind non-ArcGIS purchasing licenses and are ideally only using ArcGIS geoprocessing tools?

  • @Midavalo, first link has Dalton's answer as best which I've already referenced above as the tool that takes too long. Second link has ET Wizards as the best answer which, without a license, has a max feature count of 300. – jwx Jan 25 '17 at 16:39
  • have you looked at the suggestion on how to possibly speed up Dalton's tool? – Midavalo Jan 25 '17 at 17:58
  • 1
    Please edit your question to include any extra info rather than as comments. Please also include how long it runs using XTools for comparison. – Midavalo Jan 25 '17 at 19:26

Have you tried "Feature to Polygon", advanced license required? This tool will Cut Polygons with a Polyline FC. If you don't want the Road Network creating new polygons, first Clip the Road Network by Polygons so you are only dividing or cutting the existing Polygons.

  • Funny, I was just reading your response on a post referenced by @Midavalo. Anyways, this set me down the right path, I think. I took your idea of clipping the transit routes to the polygons of interest; however, when I ran the Feature to Polygon tool some of my polygons were so tortured that it was really hard to find a clear way of extracting the features I wanted. So, I simply buffered the clipped routes by 1 meter then used the erase tool. I can't believe I didn't think of this before. I'd like to not remove that much of the polygon, but it should be fine. – jwx Jan 25 '17 at 18:59
  • Mark as solved it @klewis suggestion helped – FelixIP Jan 25 '17 at 23:52

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.