I understand that the size of the memory of a raster database increases when reducing the cell resolution. I read some about it in the ArcGIS Help.
However, I am wondering about the exact relation on the memory footprint and was hoping that someone with more database-experience can tell me whether my reasoning here makes sense:
Given cells of 10x10 meters, and reducing the resolution to 5x5 meters, like so:
The relation for the increase of number of cells would be
n*4, so I thought that the memory increase in the database file would follow a similar pattern.
Here's my attempt to generalize this:
The amount of cells and the memory size of the database both increase by the square of the number that the sides of the initial raster cells are divided by.
2 being the divisor, thus
2^2 = 4 being the factor in this case) results in
*4 the amount of cells - so does it also result in
*4 the amount of memory size of the database?
Given that my assumption is correct, dividing a raster cell by 4, e.g.
4 being the divisor thus
4^2 = 16 being the factor), would result in
*16 the amount of cells, and
*16 the amount of memory size of the database!
That would be a large increase of file size pretty quickly!
Is this generalized formula applicable or does the size of the database increase following a different pattern - and if so, which one?