I need a Python program regarding update attributes. I have 20 shapefiles and in each shapefile, attributes to be updated based another field Example values

My requirement is to update the codes in CODE field as per the name (Example list is given right side) for 50000 features, like if name is AAA, then code will be 419, if name is ABC, then code is 420.

I have 850 different codes and I want to update all 850 at once in shapefile. I can update two or three values by using below code but I don't know how to update 850 codes.

import arcpy
from arcpy import env

env.workspace = r"C:\\data\test.shp"   
env.workspace = fc
fclist = arcpy.ListFeatureClasses()

for fc in fclist :
   fields = ["name", "code"]

   with arcpy.da.UpdateCursor(fc, fields) as cursor:
      for row in cursor:
          if row[0] == "AAA"
              row[1] =  419
          if .row[1] == "BBB"
              row[6] = 420

print "codes updated"

If I want to update all 850 codes, need to write if...else statement 850 times to update all codes. I have saved all names and codes in Excel. So instead of writing many if else statements, please help how to update all codes based on name by using Excel or CSV file.

1 Answer 1


If you need to write a lot of if statements you should consider using a dictionary instead. Code below will read a csv file and create a dictionary of names and codes and then use the dictionary in the Updatecursor for all shapefiles in a folder. Backup your data Before you try it:

import arcpy, csv

shapefile_folder = r'C:\folder'
arcpy.env.workspace = shapefile_folder
shapefile_fields_to_update = ["name","code"]

codefile = r"C:\Program123\codes.csv"

with open(codefile, 'r') as f:
    reader = csv.reader(f)
    dict = {k:v for (k,v) in reader} #Dictionary of names and codes is created here

for shapefile in arcpy.ListFeatureClasses():
    with arcpy.da.UpdateCursor(shapefile, shapefile_fields_to_update) as cursor:
        for row in cursor:
            if row[0] in dict:
                row[1]=int(dict[row[0]]) #And used here
                print "Name {0} not found in the dictionary, no update made for this name".format(row[0])

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  • Oh!. Excellent answer. it worked for me.Can you explain me about usage of dictionary in python
    – Arb
    Jan 9, 2018 at 16:20
  • Nice! Look at the link and Google "dictionary comprehension"
    – BERA
    Jan 9, 2018 at 21:18

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