I have a long code written and this is the last little bit I need and for whichever reason it does not work. This is the simple code.

arcpy.SelectLayerByAttribute_management("poligon", "NEW_SELECTION", "Id=k")

I tried a lot of different apostrphe, brackets and everything, nothing works. It says a column was specified that does not exist, Error 000358. But when I replace k with a number everything is OK. I'm at a loss of what is wrong.

  • 8
    Try "Id=" + str(k) as where_clause. Or this link can help. Apr 8 '18 at 21:26
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    – PolyGeo
    Apr 8 '18 at 21:33
  • 1
    This is because your query is looking for a field called k, which doesn't exist, hence the field not found error. @KadirŞahbaz is correct, you need to put your variable into the statement either with simple concatenation (as shown "Id=" + str(k)) or "Id={}".format(k) to insert the value of the variable into the string; either would work but I suggest that getting some exposure to format statements may benefit you as you move to more complex statements. Perhaps Kadir, you'd like to expand your comment to an answer. Apr 8 '18 at 22:05
  • 2
    @KadirŞahbaz Post this as a proper answer with a little explanation on string conversion, so we can give you the proper credits!
    – RJJoling
    Apr 8 '18 at 22:07
  • 1
    The where_clause syntax that I prefer is mentioned in @MichaelStimson's comment: "Id={}".format(k) I like that because it is so easily modified when using text fields to "Id='{}'".format(k). I also agree wholeheartedly "that getting some exposure to format statements may benefit you as you move to more complex statements".
    – PolyGeo
    Apr 8 '18 at 22:45

Error 000358means "The SQL expression is invalid", as described in Help - ArcGIS Desktop

Your query, "Id=k", means that "get Idand k (field) value of a feature, compare both, if both are equal, select that feature". Since there is no kfield in poligon layer, you encounter an error. Even if k existed as a field, any feature whose Id and kfield are equal would be selected.

But you want to select all features meet Id=2. So, you have to concatenate "Id="string and integer k for where clause.

You can do it in different ways:

k = 2
m = 3

"Id=" + str(k)     #1 "Id=2"

"Id=%s" %k         #2 "Id=2" old style

"Id={}".format(k)  #3 "Id=2" new style

"Id={0}".format(k) # by index

## multiple variables ##
"Id=%s%s" %(k, m)  # "Id=23" 

"Id={}{}".format(k, m)  # "Id=23" 

# by index, m->0, k->1
"Id={1}{0}_{1}{1}".format(m, k)  "Id=23_22" 

"Id=" + k # doesn't work. In Python, you cannot concatenate string
          # and integer in that way unlike some languages do.
  • Thanks for the answer, I have already tried number 1 and number 2 which didn't work for me, but the number three i havent thaught of and it works perfectly.
    – valsten
    Apr 9 '18 at 20:13

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