I am wondering whether it is possible to identify all neighbors to each polygon using only python (with, e.g., geopandas) in the same way that can be done with python in QGIS (Find neighbors polygon).
This code finds and adds neighbors as new field value joined by comma.
import geopandas as gp file= "C:/path/to/shapefile.shp" df = gp.read_file(file) # open file df["NEIGHBORS"] = None # add NEIGHBORS column for index, country in df.iterrows(): # get 'not disjoint' countries neighbors = df[~df.geometry.disjoint(country.geometry)].NAME.tolist() # remove own name from the list neighbors = [ name for name in neighbors if country.NAME != name ] # add names of neighbors as NEIGHBORS value df.at[index, "NEIGHBORS"] = ", ".join(neighbors) # save GeoDataFrame as a new file df.to_file("c:/path/to/newfile.shp")
This is an addendum to Kadir's answer (which works great).
For one, instead of using
not disjoint you can just use
touches directly, which does the same thing but is easier to read.
If, as the OP asked, you want to search internally to find all neighboring geometries in a single geoDataframe:
for index, row in df.iterrows(): neighbors = df[df.geometry.touches(row['geometry'])].name.tolist() neighbors = neighbors.remove(row.name) df.at[index, "my_neighbors"] = ", ".join(neighbors)
For a related capability you may want to determine whether each row of a dataframe borders some particular other shape, potentially from a different dataframe or some input value (converted into a geoDataframe).
someSpecialGeometry = GEOdataframeRow['geometry'].values df['isNeighbor'] = df.apply(lambda row: row['geometry'].touches(someSpecialGeometry), axis=1)
This creates a boolean-valued column for whether each row borders the shape of interest.