I followed the QGIS 3 cookbook and created a new custom symbol layer class. But when I try to create a new the symbol, QGIS crashes. I create it like this.

symbol = QgsMarkerSymbol({FooMarker(20)})

The link for the cookbook is the following: https://docs.qgis.org/testing/pdf/en/QGIS-testing-PyQGISDeveloperCookbook-en.pdf page: 31

My FooMarker class looks like this.

class FooMarker(QgsMarkerSymbolLayer):
    def __init__(self, radius=4.0):
        self.radius = radius
        self.color = QColor(255,0,0)

    def layerType(self):
        return "FooMarker"

    def properties(self):
        return {"radius": str(self.radius)}

    def startRender(self, context):

    def stopRender(self, context):

   def renderPoint(self, point, context):
        color = context.selectionColor() if context.selected() else self.color
        p = context.renderContext().painter()
        p.drawEllipse(point, self.radius, self.radius)

    def clone(self):
        return FooMarker(self.radius)
  • One problem is curly brackets. If QGIS keeps crashing after changing {} into [], that means you have different issue with code. As it's currently written (one line of code), it’s hard to tell exactly what problem is. Add extra explanation/code etc. to your question. You can add class FooMarker block, for example. Maybe the problem is within the class body. – Kadir Şahbaz Oct 3 '18 at 10:46
  • I have added my class to the question. – Blinxen Oct 3 '18 at 10:53

According to QGIS API Documentation QgsMarkerSymbol class needs QgsSymbolLayerList. That means a list in python.

QgsMarkerSymbol (const QgsSymbolLayerList & layers = QgsSymbolLayerList())

But you use {} and that means you pass a dictionary to QgsMarkerSymbol constructor method. If you change {FooMarker(20)} into [FooMarker(20)], QGIS doesn't crash.

  • Well that makes sense and I changed it but QGIS still crashes. – Blinxen Oct 3 '18 at 10:39
  • In QGIS 3.2.1, when I run symbol = QgsMarkerSymbol([FooMarker(20)]), QGIS doesn't crash. Are you sure you encounter crashing because of that line (symbol = ...) – Kadir Şahbaz Oct 3 '18 at 14:20

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