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I was trying to use the QgsMapToolIdentifyFeature() tool as shown in an answer of StackOverflow, but when executed it gave the error:
'QgisInterface' object has no attribute 'QgsMapToolIdentifyFeature'
I am assuming it was deprecated, in that case how do I call this tool in PyQgis3.4?
QgsMapToolIdentifyFeature is not deprecated in QGIS 3
https://qgis.org/api/classQgsMapToolIdentifyFeature.html
self.iface.QgsMapToolIdentifyFeature(atriVector, f) is not correct way,you need create a instance for QgsMapToolIdentifyFeature and set map tool after.
I add a minimal example
from qgis.gui import QgsMapToolIdentifyFeature
from PyQt5.QtGui import QColor
def onFeatureIdentified(feature):
fid = feature.id()
print ("feature selected : " + str(fid))
layer = iface.activeLayer()
mc=iface.mapCanvas()
mapTool = QgsMapToolIdentifyFeature(mc)
mapTool.setLayer(layer)
mc.setMapTool(mapTool)
mapTool.featureIdentified.connect(onFeatureIdentified)
QgsMapToolIdentifyFeature()? – Joseph Mar 20 at 13:16self.iface.QgsMapToolIdentifyFeature(atriVector, f)where atriVector=vectorLayer and f=selectedFeature – Thriskel Mar 20 at 13:28QgsMapToolIdentifyFeatureis a signal, is it right? I am looking for a way to open the IdentifyFeature tool using the selected feature, but I haven't found the actual tool yet, there are these methods:self.iface.actionIdentify().trigger(),self.iface.openFeatureForm(atriVector, f),self.iface.showAttributeTable(atriVector)but non of them opens the actual tool used in the qgis interface – Thriskel Mar 20 at 13:37