I'm trying to combine 2 raster layers using gdal_calc in order to use them in QGIS 3.8.
One of the condition that has to be met could be translated as "if the value of raster A is 1 and the value of raster B is either 10 or 11 or... or 800 (I've got 20 different values or so), then keep the value of raster B".

I managed to achieve what I wanted using several logical_and :

logical_and(A==1,B==10)*B + logical_and(A==1,B==11)*B + ... + logical_and(A==1,B==800)*B

But it's tedious to write and hard to read for other users. Is there a way to get the same result using a more compact syntax ? I tried using

logical_and(A==1,any(B==[1,10,11,12,33,35,41,42,43,44,51,52,53,222,223,224,602,700,702,710,800]))*B and logical_and(A==1,B==any([1,10,11,12,33,35,41,42,43,44,51,52,53,222,223,224,602,700,702,710,800]))*B

But neither of these gave me the same result as my previous lengthy expression...

1 Answer 1


a more compact writing could be


but this would still be quite long.

For me, any is not the good command but you could use isin (not tested)

  • 1
    Just tried it, and it works! Thank you. Would you, by chance, have any good resource suggestions to learn the commands that one can use with gdal_calc? I used scipy.org, but it's rather difficult for me to figure out what I need using this website, considering I'm not familiar with the syntax and sometimes have no idea about the name of the command I'm looking for...
    – Mefimefi
    Commented Nov 4, 2019 at 15:21
  • 1
    I am more familiar with otbcli_BandMath orfeo-toolbox.org/CookBook/Applications/app_BandMath.html , =i suggest that you have a look at it. Otherwise, you should refer to the numpy help.
    – radouxju
    Commented Nov 4, 2019 at 16:21
  • I'll have look at it. Thanks !
    – Mefimefi
    Commented Nov 5, 2019 at 9:09

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