I am trying to create a new raster from one existing raster using conditional logic, ifelse statements. The existing raster has numeric values and NA values. Here is what I tried so far, based on other posts within Stack Exchange:

f <- function(phos_all) {
        ifelse(is.na(phos_all) | NA, 
            ifelse(phos_all>=4) & (phos_all<10), 20,

phos_fert_2.5 <- calc(phos_all, fun = f, na.rm = TRUE)

When I run this code I get the following error:

Error in .calcTest(x[1:5], fun, na.rm, forcefun, forceapply) : cannot use this function. Perhaps add '...' or 'na.rm' to the function arguments?

  • What do you mean with is.na(phos_all) | NA? This is saying the same thing (NA == TRUE or NA) and there is no resulting condition. You can deal with elements that do not meet any condition by having the last condition in the nested ifelse statments be NA, which would include existing NA values. Nov 4, 2019 at 18:13

1 Answer 1


I would start with your ifelse statement. You have is.na(phos_all) | NA stating the condition [NA == TRUE or NA] which is redundant and can be dealt with at the end if the ifelse. You also have some misplaced/unnecessary parenthesis.

Let's clarify the f reclassification function a bit.

f <- function(x, ...) { 
    ifelse(x <= 4, 30,
      ifelse(x >= 4 & x < 10, 20,
        ifelse(x >= 10, 0, NA )))

Now we can test it on a vector to make sure it is yielding expected results.

y <- round(runif(100, 0, 20))
  y[c(2,50,90)] <- NA 

We can now roll it into a raster example. Note that I did add a ... argument into the f function. This can sometimes help calc and overlay with passing the function.

r <- raster(nrow=100, ncol=100)
  r[] <- round(runif(ncell(r), 0, 20)) 

( rrc <- calc(r, fun = f) )
  • Hello, Many thanks for the solution! Yup, that did it.
    – dtg37
    Nov 4, 2019 at 19:53
  • @dtg37 please accept the answer if it answered your question .
    – radouxju
    Nov 4, 2019 at 20:42

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