I have an attribute table in my layout, defined as follow :

layout = QgsPrintLayout(project)

pdf = QgsProject.instance().mapLayersByName('plan_de_ferme')[0]
pdf_table = QgsLayoutItemAttributeTable.create(layout)
pdf_fields = ['champ','sup','supepnd']
pdf_table.setDisplayedFields(pdf_fields, True)

I would like to set a background color for the header row and all even rows, as follow :

enter image description here

I can use pdf_table.setBackgroundColor(QColor(166, 206, 227, 255)) to apply a blue color for the whole attribute table but it's not what I am looking for.

attribute table 2

I think I should use QgsLayoutTable Class and QgsLayoutTableStyle Class. According to its definition, the class QgsLayoutTable has a method called setCellStyle that requires two inputs : void setCellStyle( CellStyleGroup group, const QgsLayoutTableStyle &style )

CellStyleGroup is a public type of QgsLayoutTable, defined ad follow in the first link: enter image description here

I don't know by what to replace "const QgsLayoutTableStyle &style"

I tried

                        cellBackgroundColor(QColor( 166, 206, 227, 255 )))

but I get the following error: "NameError: name 'cellBackgroundColor' is not defined",


                       QgsLayoutTableStyle().cellBackgroundColor(QColor( 166, 206, 227, 255 )))

but I get the error "TypeError: 'QColor' object is not callable",


                       QgsLayoutTableStyle.cellBackgroundColor(QColor( 166, 206, 227, 255 )))

returns "AttributeError: 'QgsLayoutTableStyle' object attribute 'cellBackgroundColor' is an instance attribute".

Like I'm not familiar with the several Python definitions, I don't understand what these means.


You need the following short snippet of code to construct a QgsLayoutTableStyle() object, set its enabled and cellBackgroundColor attributes, and then pass it as the 2nd argument to the setCellStyle() method.

table_style = QgsLayoutTableStyle()
table_style.enabled = True
table_style.cellBackgroundColor = QColor(166, 206, 227, 255)
pdf_table.setCellStyle(QgsLayoutTable.EvenRows, table_style)

Example result:

enter image description here


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