# Detecting if a point is inside a polygon with Python 3 and OGR

I am working in Python 3.7 using ogr to check if a point is inside a polygon. Here I put the code. The result in geom is not compatible with the tuple list data type used by the `point_inside` function.

How can this information be made compatible?

``````from osgeo import ogr

def point_inside_polygon(x,y,poly):

n = len(poly)
inside =False

p1x,p1y = poly[0]
for i in range(n+1):
p2x,p2y = poly[i % n]
if y > min(p1y,p2y):
if y <= max(p1y,p2y):
if x <= max(p1x,p2x):
if p1y != p2y:
xinters = (y-p1y)*(p2x-p1x)/(p2y-p1y)+p1x
if p1x == p2x or x <= xinters:
inside = not inside
p1x,p1y = p2x,p2y

return inside

file = ogr.Open("C:/Programas/Python/salida.shp/MSK_CLOUDS_B00.shp")
shape = file.GetLayer()
feature = shape.GetFeature(0)

for feature in shape:

#geom  = feature.GetGeometryRef()
geom = feature.geometry()

print (geom)

print(point_inside_polygon(-90.2,14.3,geom) )
``````
• – gene Feb 10 at 17:22

Why not use the `contains` methods on the polygon (`geom`)?

``````p1 = Point(-90.2, 14.3)

for feature in shape:
geom = feature.geometry()

if geom.contains(p1):
print(geom)
``````
• It gives me the error: File "C:/Programas/Python/puntodentrodes22.py", line 36, in <module> if geom.contains(p1): AttributeError: 'Geometry' object has no attribute 'contains' – Jose Cordovez Feb 10 at 17:31
• I'm not sure what returns: feature.geometry () – Jose Cordovez Feb 10 at 17:35

EUREKA

``````for feature in shape:

#geom  = feature.GetGeometryRef()
geom = feature.geometry()
json_geom = feature.ExportToJson()