I have a set of lat/long coordinates and need to offset the value to the "left" by < 10 meters. I calculate left by getting the direction my instrument is facing and use basic trigonometry to get the displacement in terms of lat/long. There is another similar answer on this forum but that does not talk about such small offsets. Algorithm for offsetting a latitude/longitude by some amount of meters
d_lat = shift * math.cos(math.radians(90 - theta)) d_long = shift * math.sin(math.radians(90 - theta))
How do I accurately convert this small shift from meters to latitude and longitude values? Since my offset is by less than 10 meters I need it to be fairly accurate.