In QGIS, I have a string with the pattern (1 character)(1 character)(dot)(number with 1 or more digits).

How can I use regexp_replace() to get the number only?

I tried regexp_replace('ab.27',('(\\D\\D(.))(\d)'),('\2')), but output is '?27', where I want '27'.

How to mask the dot?


As I have a longer string then just what I presented here for sake of shortness as 'ab.27' and this longer string might also contain digits, I must be able to identify the pattern mentioned above.

So the strings might look as (-> for what I want to achieve):

354ab.27 -> 27
ab.27fg87 -> 27

2 Answers 2


You can search for any char (.*), followed by a dot (\\.), followed by a number that we capture ((\\d+)) followed by any char. Replace with the captured number.


or you can search for a dot followed by a number that we capture


Original answer for a pattern of (1 character)(1 character)(dot)(number with 1 or more digits):

Instead of searching for the exact pattern, you can search for what is not a number and replace it with an empty string:


or you can look for numbers only


But if you are always having the same pattern, you can just take all chars but the first 3 ones:

  • 2
    The unfathomable depths of regular expressions.
    – Erik
    Commented Feb 9, 2022 at 14:07
  • 1
    :-) Specifically for QGIS as it is almost but not completely following the standards...
    – JGH
    Commented Feb 9, 2022 at 14:09
  • These three expressions work for the example provided, indeed. However, I have longer strings with digits before that - so I must find the pattern (char)(char)(dot)(digits). Will update the quesiton accordingly.
    – Babel
    Commented Feb 9, 2022 at 14:18

Base on your regular expression, you can use this:

regexp_replace('ab.27',('(\\D\\D\\.)'), ('')) returns 27.

ab.123456 returns 123456.

  • Indeed. However, I was not so clear in my initial question to make the issue a bit easier - see edit.
    – Babel
    Commented Feb 9, 2022 at 14:25

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