1

I first displayed a Leaflet Heatmap with the plugin : "leaflet-heat.js" and a geojson file with this code found on Gis.Stackexchange

var geoJsonUrl = "link to the geojson file"

    var geojsonLayer = $.ajax({
    url : geoJsonUrl,
    dataType : 'json',
    jsonpCallback: 'getJson',
    });

geoJson2heat = function(geojson, intensity) {
        return geojson.features.map(function(feature) {
        return [parseFloat(feature.geometry.coordinates[1]), 
                parseFloat(feature.geometry.coordinates[0]), intensity];
        });
        };
    
$.when(geojsonLayer).done(function() {
        var punti_mappa = geoJson2heat(geojsonLayer.responseJSON, 4);
        var heatMap = L.heatLayer(punti_mappa,{ 
        minOpacity: 0.9,
        radius: 7,
        gradient: {
        0.02: 'blue',
        0.2: 'cyan',
        0.3: 'green',
        0.6: 'yellow',
        0.7: 'red'
    },
    blur: 15, 
        maxZoom: 13});
        map.addLayer(heatMap);
        }); 

Now I want to display a Leaflet Heatmap with a gpx file and the "omnivore.js" plugin. I displayed the points (markers) on the map with this code

var gpxUrl = "link gpx file"
var gpxlayer = omnivore.gpx(gpxUrl).addTo(map);

but I don't know how to adapt the rest with the url to display the heatmap ?

var geojsonLayer = $.ajax({
    url : ?
    dataType : 'json',
    jsonpCallback: 'getJson',
    });

1 Answer 1

1

You have to wait for the 'ready' event of omnivore.gpx call and then use .toGeoJSON method to get GeoJSON object from your gpxlayer. This you can than use as input to geoJson2heat call.

Relevant part of the code could then look something like this:

var gpxlayer = omnivore.gpx(gpxUrl)
  .on('ready', function() {
      var geoJSON = gpxlayer.toGeoJSON();
      var punti_mappa = geoJson2heat(geoJSON, 4);
      .
      .
      .
    })
  .addTo(map);

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.