On the QGIS Field calculator, I am trying to remove from a string the text that is inside parentheses using regexp_replace.

While it is not a problem to remove the text from a string that contains only one parentheses group (using

regexp_replace('Steep (61° to 84°)','[(](.*)?[)]','')

it gives "Steep" as a result.

I am having some issues with extracting the text from a string where are present multiple parentheses, e.g.,

'Steep (61° to 84°), Vertical / Near Vertical (85° to 90°)'

From the above string, I would like to obtain

'Steep, Vertical / Near Vertical'

but if I try to use the same regex I obtain again only "steep", because for the system the closing parenthesis is the one at the end of the string.

  • What happens when you run your regexp_replace() on the whole string?
    – Erik
    Oct 12, 2022 at 11:06
  • Hi, the result is the same as the previous: steep , because for the expression the last ) is at the end of the string.
    – Val P
    Oct 12, 2022 at 11:17
  • Have you tried running the regexp_replace() on substrings, which you define by whether they are before or after the comma?
    – Erik
    Oct 12, 2022 at 11:20

2 Answers 2


You can expand your group to include the [(] and [)] by moving the inner parentheses outwards, like so:


The expression becomes:

regexp_replace('Steep (61° to 84°), Vertical / Near Vertical (85° to 90°)','([(].*?[)])','')

enter image description here

  • Thanks a lot for your answer. It solves my issue.
    – Val P
    Oct 12, 2022 at 11:24
  • Glad to help. There is a trailing space after Steep but it should be fairly simple to remove if you need to.
    – Matt
    Oct 12, 2022 at 11:26
  • Prefixing the pattern with a space seems to do the trick: ' ([(].*?[)])'
    – Matt
    Oct 12, 2022 at 11:29
  • I was using a simple replace(xxx, ' ,',',') but this is definitely a better solution. Thanks again.
    – Val P
    Oct 12, 2022 at 11:38
  • As long as the data is formatted consistently for every row, with both sets of parentheses having a space before them. Otherwise, your method might be safer :)
    – Matt
    Oct 12, 2022 at 11:45

With this expression also take into account the space after Steep:

  'Steep (61° to 84°), Vertical / Near Vertical (85° to 90°)',
  ' \\(\\d+° to \\d+°\\)','')

enter image description here

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