Usually, Euclidean distance is defined as squareroot((x1 - x2)^2 - (y1-y2)^2) but, instead of having x and y values you have a cell size of 20.
How can to calculate the Euclidean distance between the yellow boxes?
Further context:
-
1Do you know the relative position of the cells i.e. (0,0 and 4,1)?– CushenMar 14 at 0:20
-
2Are the cells always in the same relative position? Otherwise it seems like the task is to calculate the distance between two unknown locations, which seems tricky.– CushenMar 14 at 0:33
-
2In this specific case, given cell size 20 and measuring distance to/from the centre of the cells: x=20 y=60 so D= 63.245. This is a specific answer, to solve for other cases we need to know the relative position of the cells. a formula in that case would be: d = √((cellsize(cell2y-cell1y))²+(cellsize(cell2x-cell1x))²) i.e. d = √(4000 ) = 63.245– CushenMar 14 at 1:21
-
1Please add your comment as an answer so that I can accept it as an answer, thank you.– Arthur_MorganMar 14 at 2:55
-
2Jusr because cell size is fixed doesn't mean that there is no Y component. It just means that X and Y are multiples of some constant w. This is more pure math than a GIS problem.– VinceMar 14 at 11:12
|
Show 2 more comments
1 Answer
In this specific case, given cell size 20 and measuring distance to/from the centre of the cells:
x=20 y=60. Therefore: d=63.245
This is a specific answer, to solve for other cases we need to know the relative position of the cells. A formula in that case would be:
d = √( ( cellsize(cell2y-cell1y) )²+( cellsize(cell2x-cell1x) )² )
i.e. d = √(4000) = 63.245
