I want to convert a QgsPoint() to a QgsGeometry(), respectively a QgsGeometry() to a QgsPoint().

Note that I am talking about QgsPoint(), not QgsPointXY()!

QgsGeometry() does offer a .asPoint() method, but this method does not return a QgsPoint(), but a QgsPointXY(), which is quite confusing by the way. The .fromPoint() method was added in v3.34, for older versions there only is a .fromPointXY() method.

How can I do the conversion in QGIS 3.28?

Link to the docs:

2 Answers 2



from qgis.core import QgsPoint, QgsGeometry

# QgsPoint -> QgsGeometry
point_as_geom = QgsGeometry(QgsPoint(10, 20, 5, 1))
# QgsGeometry -> QgsPoint
geom_as_point = point_as_geom.constGet()

After reading this topic: Difference between QgsPoint, QgsPointXY and QgsGeometry.fromPointXY() in PyQGIS, one could think of the following approach:

from qgis.core import QgsPoint, QgsPointXY, QgsGeometry

point = QgsPoint(10, 20, 5, 1) # <QgsPoint: PointZM (10 20 5 1)>
point_as_geom = QgsGeometry.fromPointXY(QgsPointXY(point)) # <QgsGeometry: Point (10 20)>

But, it leads to missing some vital Z and M coordinates!

However, there is another solution, that was provided in this thread: Z value is lost when converting QgsGeometry to PointZ with PyQGIS. Simply pass your PointZM to the QgsGeometry() constructor.

from qgis.core import QgsPoint, QgsGeometry

point = QgsPoint(10, 20, 5, 1) # <QgsPoint: PointZM (10 20 5 1)>
point_as_geom = QgsGeometry(point) # <QgsGeometry: PointZM (10 20 5 1)>

And if one want to return, apply either get() or constGet() method that results in point (achieved with the power of QgsAbstractGeometry class):

from qgis.core import QgsPoint, QgsGeometry

point = QgsPoint(10, 20, 5, 1) # <QgsPoint: PointZM (10 20 5 1)>
point_as_geom = QgsGeometry(point) # <QgsGeometry: PointZM (10 20 5 1)>
geom_as_point = point_as_geom.constGet() # <QgsPoint: PointZM (10 20 5 1)>

In all cases, the WKB-type will be the PointZM:

from qgis.core import QgsPoint, QgsGeometry, QgsWkbTypes

point = QgsPoint(10, 20, 5, 1)
point_as_geom = QgsGeometry(point)
geom_as_point = point_as_geom.constGet()


  • 1
    It might be worth putting the two key expressions: QgsPoint to QgsGeometry: geom = QgsGeometry(QgsPoint(10,20,5,1)) and QgsGeometry to QgsPoint: geom.constGet() at the top of the answer. The discussion is useful, but I almost wrote my own answer because I didn't see the key steps Commented Feb 28 at 21:06

Indeed there is something missing and confusing, but luckily you can do both using other methods and workarounds.

To convert a QgsPoint() to a QgsGeometry() you can use WKT as an intermediate step. First convert the point to wkt by using .asWkt(), then to a geometry by using .fromWkt():

qgs_point = QgsPoint(10,20,5,1) # create or get example point
print(qgs_point) # <QgsPoint: PointZM (10 20 5 1)>
qgs_point_as_qgs_geometry = QgsGeometry.fromWkt(qgs_point.asWkt())
print(qgs_point_as_qgs_geometry) # <QgsGeometry: PointZM (10 20 5 1)>

To convert a QgsGeometry() to a QgsPoint() you can use the vertices iterator .vertices().next(), as this returns an QgsPoint():

qgs_geometry = QgsGeometry.fromWkt('PointZM (50 30 2 8)') # create or get example geometry
print(qgs_geometry) # <QgsGeometry: PointZM (50 30 2 8)>
qgs_geometry_as_qgs_point = qgs_geometry.vertices().next()
print(qgs_geometry_as_qgs_point) # <QgsPoint: PointZM (50 30 2 8)>
  • 1
    concerning your final note: fromWkb can also be used without issues, you only have to be aware that fromWkb is not a static member function like fromWkt. Therefore use geom = QgsGeometry(); geom.fromWkb(qgs_point.asWkb()) instead.
    – CodeBard
    Commented Jan 5 at 19:43

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