# How to know what value use to convert meter in degree using Google Maps info [duplicate]

This question already has an answer here:

I am trying to create a mathematical formula to convert meters to decimal degrees.

Reading this article Decimal Degrees, I thought this generic formula:

x = (Value_in_meter * 0.00001)/1.1132

But I know it is not 100% correct, I should use the other values according where is my point.

I am using Google Maps Api, so, how to discover if my point is at 23N/S, 45N/S or 67N/S?

Complementing

I did this function:

``````public static double convertMeterToDegrees(double meter, double latitude){

double quotient;
double degree = Math.floor(latitude);
double modDegree = Math.abs(degree);

if (modDegree == 0){
quotient = 1.1132;
} else if (modDegree <= 23){
quotient = 1.0247;
} else if (modDegree <= 45){
quotient = 0.7871;
} else {
quotient = 0.43496;
}

return (meter * 0.00001)/quotient;
}
``````

Is it correct?

## marked as duplicate by whuber♦Jul 18 '13 at 13:24

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

## 1 Answer

I have the belief that what you actually want to know in the end is the distance between two points. If that is the case, I have written this function in Python, and it calculates exactely the same distance along a track (accumulating distances between consecutive points of a KML file) which is returned by google maps track properties. You should check if it correctly implements the Haversine Function, though (take a look at wikipedia) since this function was written some time ago and I am not sure if it has been modified:

``````from math import *

def distance(lat1, lon1, lat2, lon2):
lat1=radians(lat1); long1=radians(long1); lat2=radians(lat2); long2=radians(long2)
EARTH_RADIUS = 6378.137
d_lat = lat2 - lat1; d_long = long2 - long1
a = sin(d_lat/2)**2 + cos(lat1) * cos(lat2) * sin(d_long/2)**2
c = 2 * atan2(sqrt(a), sqrt(1-a))

R=(EARTH_RADIUS**2)/sqrt((EARTH_RADIUS*cos(lat1))**2 + (EARTH_RADIUS*sin(lat1))**2)
return R * c
``````