I have a point layer with over 1700 features, but iterating this way:

    i = 0

    while provider.nextFeature(feat):
        i =i + 1
        print '{0} de {1}: {2}'.format(i, provider.featureCount(), feat.id())

...I get only a few of them and no error arises.

Could it be possible to make a list of feature ids and then iterating over each QgsFeature by their id()?


The while loop is not recommended in such cases, use a for loop, it is easier:

  • a layer has n features -> layer.featureCount()
  • a feature has an id -> feature.id(), a geometry and attributes

with QGIS 1.8

layer = qgis.utils.iface.activeLayer()
for feature in layer:
    geom = feature.geometry()
    attrs = feature.attributeMap()
    # the result is a dictionary
    for atr in attrs.values():
        print '{0} de {1}: {2}'.format(feature.id(), layer.featureCount(), atr.toString())

Result with one of my examples:

0 de 3: Aachen Formation
0 de 3: AAC
0 de 3: COU
0 de 3: 175
1 de 3: VAALS Formation
1 de 3: VAA
1 de 3: COU
1 de 3: 185

with QGIS 2.0

 layer = qgis.utils.iface.activeLayer()
 for feature in layer.getFeatures():
     geom = feature.geometry()
     attrs = feature.attributes()
     # the result is a list
     for elem in attrs:
         print '{0} de {1}: {2}'.format(feature.id(), layer.featureCount(), elem)

and with a dictionary, you can access the field names:

fields = layer.pendingFields()
# name of the fields
field_names = [field.name() for field in fields] 
for feature in layer.getFeatures():
    atr = dict(zip(field_names, feature.attributes()))
    print atr


{u'FORM': u'AAC', u'DESCRIPTIO': u"Aachen Formation", u'CLASSE': u'COU',u'SYMBOL': 175.0}
{u'FORM': u'AAC',  u'DESCRIPTIO': u"Vaals Formation", u'CLASSE': u'COU', u'SYMBOL': 185.0}


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.